I found an error in my calculations - here is a repost with the new values:
The biggest kit from scoobert's post makes 50 liters of hydrogen/oxygen mix per hour. Since it is separating hydrogen an oxygen from water, then it is exactly at the right percentages to be recombined during combustion. Since our motors are 8.3 liters, it would take around 24 complete revolutions (12 full cycles, 2 strokes per revolution, 4 stroke motor) at full throttle to use up an hour's worth (50 liters) of production from the kit.
So, at 6000 rpm at full throttle it would used up the full hour's production in less than 1/4 of a second.
So, lets say you just want to supplement by mainly burning gasoline/air and supplementing with hydrogen/oxygen at 10%. And, let's say that you only care about cruising speeds, steady state on the highway.
At 15 mpg at 60 mile per hour, our trucks are burning 4 gallons/hour. At 14.7:1 air fuel ratio by mass, and air at standard temp/press at .01lb/gallon, the truck is consuming 36550 gallons of air per hour plus the 4 gallons of fuel for 36554 gallons of vaporized air fuel mixture. So at 10% supplementation, it would need to produce 3655.4 gallons/hour, times 3.78 liters/gal or 13817 liters/hour.
Since the largest unit produces 50 liters/hour, you would need around 276 of them for 10% supplementation. At 20 amps draw each, that would equal 5520 Amps. At 13V, it would take 717600 watts or about 96 hp to power it (at 100% efficiency). So, you would need around 40 additional alternators and they would draw around 137hp (at 70% alternator efficiency) off the front of the motor.
All of this for only 10% supplementation at steady state highway cruising. Seems like a huge net loss to me....